Integrand size = 22, antiderivative size = 80 \[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\frac {b x}{12 c d^3 \left (1+c^2 x^2\right )^{3/2}}+\frac {b x}{6 c d^3 \sqrt {1+c^2 x^2}}-\frac {a+b \text {arcsinh}(c x)}{4 c^2 d^3 \left (1+c^2 x^2\right )^2} \]
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Time = 0.04 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {5798, 198, 197} \[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=-\frac {a+b \text {arcsinh}(c x)}{4 c^2 d^3 \left (c^2 x^2+1\right )^2}+\frac {b x}{6 c d^3 \sqrt {c^2 x^2+1}}+\frac {b x}{12 c d^3 \left (c^2 x^2+1\right )^{3/2}} \]
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Rule 197
Rule 198
Rule 5798
Rubi steps \begin{align*} \text {integral}& = -\frac {a+b \text {arcsinh}(c x)}{4 c^2 d^3 \left (1+c^2 x^2\right )^2}+\frac {b \int \frac {1}{\left (1+c^2 x^2\right )^{5/2}} \, dx}{4 c d^3} \\ & = \frac {b x}{12 c d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac {a+b \text {arcsinh}(c x)}{4 c^2 d^3 \left (1+c^2 x^2\right )^2}+\frac {b \int \frac {1}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{6 c d^3} \\ & = \frac {b x}{12 c d^3 \left (1+c^2 x^2\right )^{3/2}}+\frac {b x}{6 c d^3 \sqrt {1+c^2 x^2}}-\frac {a+b \text {arcsinh}(c x)}{4 c^2 d^3 \left (1+c^2 x^2\right )^2} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.70 \[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\frac {-3 a+b c x \sqrt {1+c^2 x^2} \left (3+2 c^2 x^2\right )-3 b \text {arcsinh}(c x)}{12 d^3 \left (c+c^3 x^2\right )^2} \]
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Time = 0.24 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.95
method | result | size |
derivativedivides | \(\frac {-\frac {a}{4 d^{3} \left (c^{2} x^{2}+1\right )^{2}}+\frac {b \left (-\frac {\operatorname {arcsinh}\left (c x \right )}{4 \left (c^{2} x^{2}+1\right )^{2}}+\frac {c x}{12 \left (c^{2} x^{2}+1\right )^{\frac {3}{2}}}+\frac {c x}{6 \sqrt {c^{2} x^{2}+1}}\right )}{d^{3}}}{c^{2}}\) | \(76\) |
default | \(\frac {-\frac {a}{4 d^{3} \left (c^{2} x^{2}+1\right )^{2}}+\frac {b \left (-\frac {\operatorname {arcsinh}\left (c x \right )}{4 \left (c^{2} x^{2}+1\right )^{2}}+\frac {c x}{12 \left (c^{2} x^{2}+1\right )^{\frac {3}{2}}}+\frac {c x}{6 \sqrt {c^{2} x^{2}+1}}\right )}{d^{3}}}{c^{2}}\) | \(76\) |
parts | \(-\frac {a}{4 d^{3} c^{2} \left (c^{2} x^{2}+1\right )^{2}}+\frac {b \left (-\frac {\operatorname {arcsinh}\left (c x \right )}{4 \left (c^{2} x^{2}+1\right )^{2}}+\frac {c x}{12 \left (c^{2} x^{2}+1\right )^{\frac {3}{2}}}+\frac {c x}{6 \sqrt {c^{2} x^{2}+1}}\right )}{d^{3} c^{2}}\) | \(78\) |
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Time = 0.27 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.22 \[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\frac {3 \, a c^{4} x^{4} + 6 \, a c^{2} x^{2} - 3 \, b \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) + {\left (2 \, b c^{3} x^{3} + 3 \, b c x\right )} \sqrt {c^{2} x^{2} + 1}}{12 \, {\left (c^{6} d^{3} x^{4} + 2 \, c^{4} d^{3} x^{2} + c^{2} d^{3}\right )}} \]
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\[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\frac {\int \frac {a x}{c^{6} x^{6} + 3 c^{4} x^{4} + 3 c^{2} x^{2} + 1}\, dx + \int \frac {b x \operatorname {asinh}{\left (c x \right )}}{c^{6} x^{6} + 3 c^{4} x^{4} + 3 c^{2} x^{2} + 1}\, dx}{d^{3}} \]
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\[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} x}{{\left (c^{2} d x^{2} + d\right )}^{3}} \,d x } \]
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\[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} x}{{\left (c^{2} d x^{2} + d\right )}^{3}} \,d x } \]
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Timed out. \[ \int \frac {x (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int \frac {x\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}{{\left (d\,c^2\,x^2+d\right )}^3} \,d x \]
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